This is a basic Python program to calculate how much solute is needed to make a particular concentration of a chemical for a given solution.

Enter mass of chemical, volume and concentration required. Program will calculate required solute needed.

#Chemical solute calculator
print("Chemical solute calculator")
print(" ")
print("This program will ask you for some basic data and will then calculate how much solute is needed for a given volume and concentration")
print(" ")
print("1 mol solution is formula weight in 1 liter of water")
print("")
print(" ")
print("Mass is the molecular mass of the chemical solution you're making e.,g Copper Sulfate is 249g")
print(" ")
print("Volume the total solution volume in litres,  100ml is written as 0.100")
print(" ")
print("Concentration required in Mols")
print(" ")
mass = input ("Mass in g: ") 
#print("Solute requred")
volume = input("Volume in l: ")
print((volume) + " l")
conc = input ("Required Concentration in M: ") 

solute = float(mass) * float(volume) * float(conc)
print("Solute required: ")
print(str(solute) + " g")
print(" ")
print("Note:  This program is a guide, and you should double check calculations")

There is a better online solution to this here

Program 2

This is a related ruby program to calculate different molar masses

# molar weight calculator
puts "molecular weight calculator"
puts
print "Enter Weight: "
weight = gets
print ("Weight :"); 
print (weight)
puts 
print ("0.5 Mol: ")
print weight.to_f / 2
puts
print ("2 Mol: ")
print weight.to_i * 2
puts 
print ("4 Mol: ")
print weight.to_i * 4
puts
puts 
print ("End")

Enter a molecular weight, and it will calculate ½, 2 and 4 moles accordingly. It is not perfect, just works.

Tags

#Science,#Chemistry,#Calculator,#Mole,#Solution,#Solute

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There is website tool for calculating the amount of solute needed for a given volume and concentration. This can be found here

I just put this together in python3

V2.0

#Chemical solute calculator
print("Chemical solute calculator")
print(" ")
print("This program will ask you for some basic data and will then calculate how much solute is needed for a given volume and concentration")
print(" ")
print("1 mol solution is formula weight in 1 liter of water")
print("")
print(" ")
print("Mass is the molecular mass of the chemical solution you're making e.,g Copper Sulfate is 249g")
print(" ")
print("Volume the total solution volume in litres,  100ml is written as 0.100")
print(" ")
print("Concentration required in Mols")
print(" ")
mass = input ("Mass in g: ") 
#print("Solute requred")
volume = input("Volume in l: ")
print((volume) + " l")
conc = input ("Required Concentration in M: ") 

solute = float(mass) * float(volume) * float(conc)
print("Solute required: ")
print(str(solute) + " g")
print(" ")
print("Note:  This program is a guide, and you should double check calculations")

#Chemical solute calculator
print("Chemical solute calculator")
print(" ")
print("This program will ask you for some basic data and then calculate how much solute is needed for a given volume and concentration")
print(" ")
mass = input ("Mass in g: ") 
print("Solute requred")
volume = input("Volume in l: ")
print((volume) + " l")
conc = input ("Required Concentration in M: ") 


solute = float(mass) * float(volume) * float(conc)
print(solute)

Note: This is just meant to work and perform a single function. I have not added error checking, so values are numerical.

Tags

#Calculator,#Solute,#Chemistry,#Solution,#Volume,#Mols

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I decided to write this to help calculate molar weights for chemistry.

In essence you can enter the Mass of an element or molecular mass of a substance, compound etc, and this will help give you molar weight, for example 0.5 mol.

It is, for example common to have different concentrations of an acid for example. We know that Sodium Hydroxide has a weight of 40 because of the combined weight of its components:

$NaOH$ which equates to

Na = 22 + O = 16 + H = 1 = 39

Therefore 1 mol of NaOH = 39g which is of course equal to Avogadros constant : $6.022 x 10^{23}$

Therefore 0.5 mol is roughly $39 \div 2 = 19.5g$

This program is NOT a substitute for proper calculation. You need to use more accurate values. Values used are just a rough guide.

However it may be useful, for those quick calculations.

The program code base is taken from my Drake equation calculator I made a few weeks ago.

#chemistry,#mol,#molar,#weight,#calculator

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AI statement : Consent is NOT granted to use the content of this blog for the purposes of AI training or similar activity. Consent CANNOT be assumed, it has to be granted.