Home Chemistry 19 part 1
How to calculate what is needed for a displacement reaction to take place.
I asked this on Science forums but this is the basis of my question
I have some Copper Sulfate in solution, along with various metallic elements which should produce a displacement reaction for example
Rough equations@-
- CuSO_4 + Mg => MgSO4 + Cu
- CuSO_4 + Zn => ZnSO4 + Cu
- CuSO_4 + Al => AlSO4 + Cu
If I make up a 0.1 molar solution of Copper Sulfate at 100ml volume I need 2.49g of Copper Sulfate in 100ml water. This is fine.
Now if I wanted to add just enough of one of the above metals to displace all the copper do I calculate as follows
( I could look this up, but I have an idea of how to do this, so am asking to see if I am on the right track)
- 1 M of Copper sulfate weighs 249g
- Mass of copper is 63.54 g then calculating the % composition gives
- 63.54 / 249 = 0.26 x 100 = 26%
So if I have a 0.1 M solution, and used 2.49 g of the copper sulfate do I then work out what 26% of that is with
- 0.26 x 2.49 = 0.65g
Therefore I need 0.65g of one of the above elements to displace the Copper
I think that I am nearly there with this, but given Magnesium , Aluminium and Zinc all have different weights, do I need to factor in the atomic mass of the element I am using for the displacement ?
Or just weigh out say 0.65g of Magnesium to produce
CuSO4 5H2O (solution) + Mg = MgSO4 (solution) + Cu + H20
I am not quite sure what happens to the 5H_2O here.
Am I right on my thinking here ?
#Chemistry,#HomeChemistry,#HomeChemistry19
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