# herbert-quain

## August 29, 2019

Testing MathJax

When $a \ne 0$, there are two solutions to (ax^2 + bx + c = 0) and they are: $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$

$$\int_0^\infty \frac{x^3}{e^x-1}\,dx = \frac{\pi^4}{15}$$

This should be inline: $ax^2 + \sqrt{bx} + c = 0$

Hi $z = x + y$.

$$a^2 + b^2 = c^2$$

$$\begin{vmatrix}a & b\\ c & d \end{vmatrix}=ad-bc$$

e have $x_1 = 132$ and $x_2 = 370$ and so ...

\begin{array}{cc} a & b \\ c & c \end{array}

When (a \ne 0), there are two solutions to (ax^2 + bx + c = 0) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

When (a \ne 0), there are two solutions to (ax^2 + bx + c = 0) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

... when $x < y$ we have ...

## Hello World

Hello! This is my first post. I am actually posting this from the command line through an API Client library I am working on for Write Freely.